(3x-1)*(4x+7)=12x^2+-4x-7

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Solution for (3x-1)*(4x+7)=12x^2+-4x-7 equation: 



(3x-1)(4x+7)=12x^2+-4x-7

We move all terms to the left:

(3x-1)(4x+7)-(12x^2+-4x-7)=0

We use the square of the difference formula

(3x-1)(4x+7)-(12x^2-4x-7)=0

We get rid of parentheses

-12x^2+(3x-1)(4x+7)+4x+7=0

We multiply parentheses ..

-12x^2+(+12x^2+21x-4x-7)+4x+7=0

We get rid of parentheses

-12x^2+12x^2+21x-4x+4x-7+7=0

We add all the numbers together, and all the variables

21x=0

x=0/21

x=0

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